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IFoS · Paper I · Mechanicsifos-2024-subject-01-006

Moment of inertia — UPSC Physics Optional IFoS 2024 Paper I

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The moment of inertia tensor of a cube of mass M and side a is given by the matrix I = \frac{M a^2}{12} \begin{bmatrix} 8 & -3 & -3 \\ -3 & 8 & -3 \\ -3 & -3 & 8 \end{bmatrix}. Calculate the principal moments of inertia of the cube.

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