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CSE · Paper II · Atomic & Molecularcse-2025-subject-06-007

Force constant — UPSC Physics Optional CSE 2025 Paper II

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The force constant of \text{HCl} molecule is 4\cdot 8 \times 10^5 \text{ dyne/cm}. Calculate the wave numbers of Stokes and anti-Stokes lines, when excited with a radiation of wavelength 4358 \text{ \AA}. [ Given, \mu_{\text{HCl}} = 1\cdot 61 \times 10^{-24} \text{ g} ]

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