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CSE · Paper II · Atomic & Molecularcse-2020-subject-06-005

Potential energy — UPSC Physics Optional CSE 2020 Paper II

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The potential energy of a diatomic molecule in terms of the interatomic spacing R is given by U(R)=-\frac{A}{R^2}+\frac{B}{R^{10}} where A=1.44\times10^{-3}\,\mathrm{J\,m^2} and B=2.19\times10^{-115}\,\mathrm{J\,m^{10}}. Calculate the equilibrium spacing, R_e and the dissociation energy.

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