Joule–Thomson effect — UPSC Physics Optional CSE 2006 Paper I

Using thermodynamic principles show that the Joule-Thomson coefficient \mu can be expressed as \mu = \frac{1}{C_p} \left[ T \left( \frac{\partial V}{\partial T} \right)_p - V \right] . Calculate the value of \mu for an ideal gas and interpret your result physically.