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CSE · Paper I · Waves & Opticscse-1987-subject-02-003

Fourier series — UPSC Physics Optional CSE 1987 Paper I

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Fourier analyse the step-function f(x) = 1 \text{ for } 0 < x < \pi = -1 \text{ for } \pi < x < 2\pi and hence prove that 1 + \frac{1}{9} + \frac{1}{25} + \frac{1}{49} + \dots = \frac{\pi^2}{8}

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