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CSE · Paper II · Quantum Mechanicscse-2008-subject-05-005

Wave number — UPSC Physics Optional CSE 2008 Paper II

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Show that the probability of transmission across the step barrier represented by the potential V(x) = \begin{cases} 0 & \text{for } x < 0 \\ V_0 & \text{for } x > 0 \end{cases} is T = \frac{4 k_1 k_2}{(k_1 + k_2)^2}, where k_1 and k_2 are wave numbers in regions x < 0 and x > 0, respectively.

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