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CSE · Paper I · Mechanics

Central Force Motion and Kepler Orbit Equation

Two-Body Central Force Problem

The equation of orbit under inverse-square law (r) = -k/r^2$ is: 2497747\frac{d^2 u}{d\theta^2} + u = \frac{m k}{L^2}2497747

Conic section solution: 2497747r(\theta) = \frac{p}{1 + e \cos\theta}2497747

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@physicist_5034Sep 21, 12:50

Excellent derivation of the Binet equation!

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